Math, asked by limits, 1 year ago

find x, limx-0^+ (sinx)^tanx

Answers

Answered by abhi178
2
lim(x→0⁺) sinx^tanx

⇒lim(x→0⁺)e^tanx.㏑sinx

⇒e^lim(x→0⁺){ lin sinx/cotx }
⇒e^lim(x→0⁺){cosx/sinx.(-cosec²x)}
⇒e^lim(x→0⁺){-sinx.cosx}
       now put x0
= e⁰ = 1 
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