Question

find 'x' please ... help ​

Answer 1

Answer:

angle MBC+angleCBD=180

=>70+CBD=180

=>CBD=180-70

=>CBD=110

in ΔBCD,

ANGLE BCD=30

ANGLE CBD=110

ANGLE BDC(X)=180-(30+110)

=180-140

=40

Hence X is 40 degree

Answer 2

❄️ Solution :

To find the value of x, first let's find $\sf \angle B$

$\sf \angle B = 70° - 180° \: \: \: \: \: \sf(linear \: \: pair) \\ \\ \sf \: \angle B = \: 110°$

Now, let's find x.

$\\ \sf \angle B+ \angle C + \angle D = 180 \degree \\ \sf(angle \: \: sum \: \: property) \\ \\ \sf 70\degree + 30\degree + x = 180\degree \\ \sf \: x = 180\degree - 100\degree \\ \sf x = 80\degree$

Now let's verify our answer :

∠B + ∠C + ∠D = 180°

(Angle sum property)

→ 70° + 30° + 80° = 180°

→ 180° = 180°

.°. LHS = RHS

Hence, verified

So, the value of x = 80°