find x pls it's urgent
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in triangle COA
SIDE OC = SIDE OA - > ( RADII OF SAME CIRCLE
therefore by isosceles triangle theorem
angle OCA = angle OAC. ( 1 )
ANGLE AOB IS EXTERIOR ANGLE OF TRIANGLE AOC
THEREFORE BY THEOREM OF REMOTE INTERIOR ANGLE
angle AOB = angle OAC + angle OCA
80⁰ = angle OAC + angle OAC -> [ from ( 1 ) ]
80⁰ = x + x
2 x = 80⁰
x = 80 / 2
x = 40⁰
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