Question

find x : sin²x-sinx=0​

Answer 1

Answer:

if sinx is 0 then  x = 2 n π  , n = natural number

if sinx is not 0 then, cancel sin x on both sides,

cos² x - 2 sin x = 3

-  sin² x - 2 sin x - 3 =0 

sin² x + 2 sin x -1 = 0

Δ = 4 + 16 = 20

sin x = (-2 +- 2√5) / 8    =  (-1 +- √5) / 4  = 

 x =  2 n π + 18 deg  or  2 n π (- 54 deg  = 126 deg)

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