Find x so that x , x+2 , x+6 are consecutive terms of a geometric progressions (show work please)
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what is the value of x in this
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x+2/x =x+6/x+2
x(x+2)+2(x+2)=x(x+6)
x^2+2x+2x+4=x^2+6x
x^2+4x+4-x^2-6x=0
-2x+4=0
-2x=-4
2x=4
x=4/2
x=2
Hope This helps you
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