Find x
sothat 9, x, 4 are consecutive terms of a G.P. solve cheyyu
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Answer:if the terms are in gp then they are in the form:
a, a.r, a.r²,so on......
here terms are 9,x,4
Therefore,a=9; a.r=x; a.r²=4
a.r²/a=4/9
r²=4/9
√r²=√2*2/3*3
r=2/3
a.r²/r=a.r
4/(2/3)=x
4*3/2=x
x=2*3
x=6
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