Question

Find x Such That (3/5)^3×(3/5)^-6=(3/5)^2x-1

Answer 1

(3/5)^3 * (3/5)^-6 =
(3/5*3/5*3/5)*(5/3*5/3*5/3*5/3*5/3*5/3)=
(5/3*5/3*5/3)=
(3/5)^-3 = (3/5)^(2x-1) (given)
therefore
-3=2x-1
2x=-2
x=-1

Answer 2

(3/5)³ × (3/5)^-6 = (3/5)^2x-1

(3/5)^3+(-6) = (3/5)^2x-1

(a^m×aⁿ = a^m+n)

Bases are equal. Exponents must be equal.

3+(-6) = 2x-1

3-6 = 2x-1

-3 = 2x-1

2x = -3+1

2x = -2

x = -2/2

x = -1

Hope it helps