Question

find x value of (x+1)(6-x)+(x-8)(x-12)=0​

Answer 1

Answer:

(x+1)(6-x)+(x-8)(x-12)=0

[6x-x^2+6-x]+[x^2-12x-8x+96]=0

[-x^2+5x+6]+[x^2-20x+96]=0

-x^2+5x+6+x^2-20x+96=0

-15x+102=0

-15x=-102

x=102/15

x=34/5