Math, asked by Vinod6407, 11 months ago

Find x when 3^2x-1=1/27^-x-7

Answers

Answered by ysprakash2001
0

Answer:

-22

Step-by-step explanation:

3^2x-1=1/27^-x-7

= 3^2x-1=1/27^-1(x+7)

=3^2x-1=(1/27)^-1(x+7)

=3^2x-1=27^x+7

=3^2x-1=3^3(x+7)

3^2x-1=3^3x+21

bases are equal so powers are also equal

2x-1=3x+21

3x-2x=-1-21

x=-22

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