Question

find X with complete steps

Answer 1

hey bro!
#ur solution :
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$= > {4}^{x - 1} \times {0.5}^{3 - 2x} = ( \frac{1}{8} {)}^{x} \\ \\ now \\ \\ = > {2}^{2(x - 1)} \times (\frac{1}{2} ) {}^{3 - 2x} = ( \frac{1}{ {2}^{3} } ) {}^{x} \\ \\ = > {2}^{2x - 2} \times {2}^{ - 1(3 - 2x)} = {2}^{ - 3x} \\ \\ now \: here \: is \: base \\ \: is \: same \: then \: we \: can \\ \: solve \: the \: power \: value \\ \\ = > 2x - 2 - 3 + 2x = - 3x \\ \\ = > 4x - 5 = - 3x \\ \\ = > 4x + 3x = 5 \\ \\ = > 7x = 5 \\ \\ = > x = \frac{5}{7} \: ans$
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