Question

find x.

x/root128 = root162/x

Answer 1

Hey!

$\frac{x}{\sqrt{128}}=\frac{\sqrt{162}}{x}\\\\x^2 = \sqrt{128\times162}\\x^2 =\sqrt{64\times2\times18\times9}\\x^2 = \sqrt{8\times8\times\times6\times6\times2\times2}\\x^2 = 8\times4\times2\\x^2 = 144\\x=\sqrt{144}\\x = 12$

Answer 2

Given-
$\frac{x}{ \sqrt{128} } = \frac{ \sqrt{162} }{x}$
To find-The value of x

SOLUTION :
$x { }^{2} = \sqrt{128 \times 162} \\ x {}^{2} = \sqrt{64 \times 2 \times 18 \times 9} \\ x {}^{2} = \sqrt{8 \times 8 \times 6 \times 6 \times 2 \times 2} \\ x {}^{2} = 8 \times 4 \times 2 \\ x {}^{2} = 144 \\ x = \sqrt{144 } \\ x = 12$

Answer: Hence, the value of x is 12

-Ekansh Nimbalkar