find X , y and z from this figure.
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angle x=53°(alt. angle)
angle x + angle Y=127°(exterior angle is equal to sum of the opposite two interior angle)
therefore, angle Y =127°-53°=74°
now in ∆,angle x +angle Y+ angle z=180°
therefore,angle z=180-(74°+53°)
=53° ANS
angle x + angle Y=127°(exterior angle is equal to sum of the opposite two interior angle)
therefore, angle Y =127°-53°=74°
now in ∆,angle x +angle Y+ angle z=180°
therefore,angle z=180-(74°+53°)
=53° ANS
Answered by
0
y=127-53
=74
z + (y+53)=180 (co - interior angle)
Z=53
x=53 ( sum of interior angles of triangle)
=74
z + (y+53)=180 (co - interior angle)
Z=53
x=53 ( sum of interior angles of triangle)
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