Find x:y if :x3+3xy2/y3+3x2y=63/62
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Answer:
Step-by-step explanation:
We have
a3 + 3ab2/b3 + 3a2b = 63/62
App. Componendo and Dividendo
a3 + 3ab2 + b3 + 3a2b/ a3 + 3ab2 - b3 - 3a2b = 63 + 62/63 – 62
a3 + b3 + 3ab2 + 3a2b/a3 + 3ab2 - b3 - 3a2b = 125/1
(a + b)3/(a – b)3 = 125/1
a + b/a – b = 5/1
Again Applying Componendo and Dividendo
a + b + a – b/a + b – a + b = 5 + 1/5 – 1
2a/2b = 6/4
a : b = 3 : 2
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