Math, asked by bandinaga16, 3 months ago

Find x+y, whole root 11. -3√8 =x+y√2

Answers

Answered by uttamratrey007
0

whole square root 1-sin2x/1+sin2x, then dy/dx

Answered by islamjaha949
0

Answer:

If y – 2 = 6, what is y + √4?

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y - 2 = 6 implies that y = 8 (after adding 2 to each side)

y - 2 + 2 = 6 + 2

y = 8

√4 has two roots: +2 and -2

so y + √4 has two answers

y + √4

= y + ( +2 )

= 8 + ( +2 )

= 10 first answer

y + √4

= y + ( -2 )

= 8 + ( -2 )

= 6 second answer

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