Math, asked by ajmalmustafa625, 4 months ago

find x:y:z if x:y=4/3:5/4 y:z=6:3/4​

Answers

Answered by bson
4

Step-by-step explanation:

x:y = 4/3 : 5/4

=16/12: 15/12

= 16:15

=16×8:15×8

=128:120

y:z = 6 : 3/4

=24:3

=24×5:3×5

=120 : 15

x:y = 128:120

y:z = 120:15

x:y:z = 128:120:15

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