Question

Find x, y, z in the following figure.​

Answer 1

Answer:

in this figure we are given that BE=BD

angle E=angleD( angles opp to equal sides in a triangle)

50 +A+A=180(angle sum property)

A=75=angleE=angleZ

angle y=angleE and angle x=anglez

because ACparallel toEd

and BD and BE are transversals

so angles are equal because they are pair of alternate ang

angx=angy=angz=75 degree

pls mark brainliest

Answer 2

$\huge{\underline{\underline{\mathfrak{Answer : }}}}$

$\angle{x}$ = $\angle{y}$ = $\angle{z}$ = 65°

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$\huge{\underline{\underline{\mathfrak{Explanation : }}}}$

As, From the figure we can see that $\angle{x}$ = $\angle{y}$ ( Vertical Opposite angles). Let the $\angle{x}$ and $\angle{y}$ be a.

So, A.T.Q

$\sf{\implies a + 50° + a = 180° } \\ \sf{\implies 2a = 180 - 50} \\ \sf{\implies 2a = 130} \\ \sf{\implies a = \dfrac{\cancel{130}}{\cancel{2}}} \\ \sf{\implies a = 65°}$

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Now, $\angle{BED}$= $\angle{BDE}$ ( Angles opposite to equal side in a triangle BE || BD.

So, Let $\angle{BED}$= $\angle{BDE}$ be b.

$\sf{\implies b + 50° + b = 180° ( Angle \ sum \ property)} \\ \sf{\implies 2b = 180 - 50} \\ \sf{\implies 2b = 130} \\ \sf{\implies b = \dfrac{\cancel{130}}{\cancel{2}}} \\ \sf{\implies b = 65°}$

$\LARGE{\underline{\underline{\boxed{\sf{ x = y = z = 65°}}}}}$