find x + y + z + w in the figure.
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Answered by
1
Since, the sum of the measures of interior angles of a quadrilateral is 360
∘
Also,115
∘
+70
∘
+60
∘
=245
∘
∴∠ABC=360
∘
−245
∘
=115
∘
Now, x=ext∠BCD
=180
∘
−115
∘
=65
∘
y=180
∘
−70
∘
=110
∘
z=180
∘
−60
∘
=120
∘
w=180
∘
−115
∘
=65
∘
∴x+y+z+w=65
∘
+110
∘
+120
∘
+65
∘
=360
∘
Answered by
16
Answer:
all the exterior angles of the parallelogram add upto 360°
y=180-85(linear pair )
y=95°
x=180-110(linear pair)
x=70°
z=90° (right angle)
so, x+y+z+w =360°
70+95+90+w =360°
255+w=360°
w=360-255
=105°
so, x+y+z+w=360°
70+90+95+105=360°
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