find x° from the following
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Answer:
144°
Step-by-step explanation:
∠BAE = 54° [given]
BA = BE
⇒∠BEA = 54° [angle opposite to equal sides are equal]
∠CBE = 54° +54° [exterior angle property of a triangle]
= 108°
⇒BC = BE [given]
∠BEC = ∠BCE
⇒∠BEC + ∠BCE + 108° =180° [angle sum property of a triangle]
2∠BCE = 72°
∠BCE = 36°
x° + 36° = 180° [linear pair]
x° = 144°
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