Math, asked by agrawalrajesh123446, 3 months ago

find x° from the following​

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Answered by sajal09
0

Answer:

144°

Step-by-step explanation:

∠BAE = 54°  [given]

BA = BE

⇒∠BEA = 54°  [angle opposite to equal sides are equal]

∠CBE = 54° +54°  [exterior angle property of a triangle]

          = 108°

⇒BC = BE   [given]

∠BEC = ∠BCE

⇒∠BEC + ∠BCE + 108° =180°  [angle sum property of a triangle]

2∠BCE = 72°

∠BCE = 36°

x° + 36° = 180°  [linear pair]

x° = 144°

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