find x° in this figure
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triangle qsr
q+r=110(q=r=55)
in triangle qpr
q+r=140
q=r=70
hense 70-55=15degree
tnx
q+r=110(q=r=55)
in triangle qpr
q+r=140
q=r=70
hense 70-55=15degree
tnx
Answered by
1
180-40
=140/2
=70
180-70
=110/2
=55
70-55=15
x=15
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