Find x2+1/x2 if x-1/x=√3
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x - 1/x = √3
Sqauring both sides
(x - 1/x)² = (√3)²
=> x² + 1/x² +2(x)(1/x) = 3
=> x² + 1/x² + 2 = 3
=> x² + 1/x² = 3-2
=> x² + 1/x² = 1
hope it helps dear friend
Sqauring both sides
(x - 1/x)² = (√3)²
=> x² + 1/x² +2(x)(1/x) = 3
=> x² + 1/x² + 2 = 3
=> x² + 1/x² = 3-2
=> x² + 1/x² = 1
hope it helps dear friend
utkarshbhardwaj82688:
Thank you so much for your help
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