Question

find Y if (9/4 ) ^2y-1 × (8 / 27) ^5 = (3 / 2) ^ Y + 2​

Answer 1

Answer:

y=3

Step-by-step explanation:

(3/2)^8y-4 ×( 2/3)^15=(3 / 2) ^ Y + 2

(3/2)^8y-4 × (3/2)^-15=(3 / 2) ^ Y + 2

(3/2)^ 8y-4-15=(3 / 2) ^ Y + 2

by comparing

8y-19=y+2

7y=21

y=3

Answer 2

Answer:

y =7 ....answer

‍(9/4)^²y–1 × (8/27)^5 = (3/2)^y+²‍

solve and get answer with your own HANDD