Find 'y', if the distance between the points (2, -3) and (10, y) be 10 units
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Here is the answer to your question:
Given: AB=10units , A=(2,-3) ,B=(10,y)
To find : Value of y
Solution: The distance AB=√(x2-x1)^2 + (y2-y1)^2
Putting the values in the formula
AB=√(10-2)^2 + (y+3)^2
√8^2+y^2+6y+3^2 = 10
(Squaring both sides)
64+y^2+6y+9=100
y^2+6y+73=100
y^2+6y-27=0
By splitting the middle term
y^2-3y+9y-27=0
y(y-3)+9(y-3)=0
(y+9)(y-3)=0
either y+9=0 or y-3=0 to make to whole equation 0
Therefore y=(-9) or 3
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