Question

Find y: logy25-logy5+log1/125=2

Answer 1

Answer:

Y=2.718

Step-by-step explanation:

log25=log5^2=2log5

log Y5=logy+log5

log(1/125)=log 1 -3log 5

log (Y 25)=logy +2log5

Therefore

logy25-log (Y5)+log(1/125)=2

or,logY+2 log5+log Y+log 5+log 1-3log 5=2

or,2log Y=2

or,log Y =1

or Y=e^1

orY=2.718(approx)

I hope it's may help you.