Question

find y=x^2_x^3 minimum maximum values​

Answer 1

y = X square+ y

for minimum value of y

dy / dx should be zero

dy / dx = 2 X + 1

2 X + 1 = 0

2 X = -1

X = -1/2

sub X= -1/2 is y to get minimum value

y = (-1/2) square+ (-1/2)

=1/4-1/2

= 1-2/4 = y= -1/4

it is the minimum value of y

hope it it will help you

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