find y²+1/y² and y⁴+1/y⁴,if y-1/y=5
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Answered by
4
Answer:
y^2+1/y^2
=(y-1/y)^2+2.y.1/y
=(5)^2+2
=25+2
=27
y^4+1/y^4
=(y^2+1/y^2)-2.y^2.1/y^2
=(27)^2-2
=729-2
=727
Answered by
3
y-1/y=5
on square
y²+1/y²-2=25
y2+1/y²=27
by formula
( a-b)³=(a-b)(a²+b²+ab)
y³+1/y³=130
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