QUESTION 90:
Certain ges at pressure p atm is enclosed in a vessel having tetragonal shape lflength of the sides
which are equal are decreased by two times and the length of other side increases by four times. Then
the pressure of the gas inside the vessel is
4P 3 at
3P 4 atm
2 atm
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The correct answer is P.
Given: Pressure inside the closed vessel = P.
To Find: The pressure after changing dimensions of vessel.
Solution:
The Ideal gas equation,
PV = nRT (equation 1)
Initially,
Pressure = P
Volume = V
Moles = n
R is constant
Temperature = T.
Finally, as dimensions of enclosed vessel was changed so the volume remains same.
And rest all the things are same as initially.
Pressure = ?
Volume = V
Moles = n
R is constant
Temperature = T.
(Pressure)V = nRT
Now, put the value of nRT from equation 1.
(Pressure)V = PV
Pressure = P
Hence, the final pressure remains same.
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