Question

Find yhe equation of circle x^2+y^2 +4x+6y+11 and passing through 5,4

Answer 1

Answer:

Step-by-step explanation:

x=5,y=4

(5)^2+(4)^2+4*5+6*4=11

25+16+20+24=11

25+16+20+24-11=0

74=0.  

i.e is the equation for concentratic circle is 4x+6y=74-11

4x+6y=63