Question

Find z1/z2 ,when z1 = ( 6 + 3i) and z2 = ( 3-i )

Answer 1

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Answer 2

The value is $\frac{z_1}{z_2}=\frac{3+3i}{2}$

Step-by-step explanation:

Given : $z_1=6+3i$ and $z_2=3-i$

To find : The value of $\frac{z_1}{z_2}$ ?

Solution :

Expression $\frac{z_1}{z_2}$

Substitute, $z_1=6+3i$ and $z_2=3-i$

$\frac{z_1}{z_2}=\frac{6+3i}{3-i}$

Rationalize,

$\frac{z_1}{z_2}=\frac{6+3i}{3-i}\times \frac{3+i}{3+i}$

$\frac{z_1}{z_2}=\frac{18+6i+9i+3i^2}{3^2-i^2}$

$\frac{z_1}{z_2}=\frac{18+15i-3}{9+1}$

$\frac{z_1}{z_2}=\frac{15+15i}{10}$

$\frac{z_1}{z_2}=\frac{3+3i}{2}$

Therefore, the value is $\frac{z_1}{z_2}=\frac{3+3i}{2}$

#Learn more

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