find zero of polynomial x^2 - under root 2 +1/3
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Step-by-step explanation:
I am going to solve this question by quadratic formula
Quadratic formula= [-b+-√(b^2-4ac)]/2a
Here a= coefficient of x^2 = 1
b=coefficient of x =-√2
C= constant term
So,put the values of a,b,c in given formula
x = [√2+√(2-4/3)]/2 [ as it has 2 value of zeros .so,we will take '+' first . And find the value of x then we will take 'Minus' and solve for value of x .
After solving
X= [√6+√2]/2√3
And
X= [√6-√2]/2√3
lakshay4923:
sorry I have not understood
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