Question

Find zero of the polynomial 2-3x^2​

Answer 1

$2 - 3x {}^{2} = 0 \\ = > 3x {}^{2} = 2 \\ = > x {}^{2} = \frac{2}{3} \\ = > x = ( + - ) \sqrt{ \frac{2}{3} } \\ = > x = \sqrt{ \frac{2}{3} } \: or \: x = > - \sqrt{ \frac{2}{3} }$

Hope it helps... thanks

Answer 2

here's your answer hope you like it