find zero of the polynomial 5x square +2x-7
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here it is!!!!
= 5x^2+12x+7
= 5x^2+5x+7x+7
= 5x(x+1)+7(x+1)
=) (5x+7)(x+1) so there fore zeroes are x=-1,-7/5
NOW verifications
SO
sum of zeroes = = -b/a
= -1+(-7/5)=-12/5
=) -12/5=-12/5
LHS=RHS
now
product of zeroes!!!!
product =c/a
(-1)(-7/5)=7/5
7/5=7/5
LHS=RHS
hence showed!!!!!!!!!!!
hope it will help you
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