find zero of the polynomial: x^2-3x+2
Answers
Hi
Solution :- x² - 3x + 2 =0
=> x² - 2x - X + 2 =0
=> x ( x - 2) - 1 ( x - 2 ). = 0
=> (x - 2 ) ( x - 1)
=> x = 2 and x = 1
x has two real zeroes
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Hope it helps !
Solution:-
Given Quadratic Polynomial Equation:-
x² - 3x + 2 = 0
To Find :-
Zeroes of the Given polynomial.
Find:-
=) x² - 3x + 2 = 0
=) x² - ( 2 + 1)x + 2 = 0
=) x² - 2x - x + 2 = 0
=) x ( x - 2) -1 ( x -2)
=) ( x -2) ( x -1)
=) [ x = 2 ] and [ x = 1 ].
Steps to Solve Questions by splitting the Middle term Method.
(1) Firstly, we splitt the Middle term of the Equation such as the sum of Splitted term is equal to the term.
Ex :- Middle Term (3x).
After Splitting:- ( 2 + 1)x
(2) We also see that the Product of the Splitted term must be equal to the Product of First and the last term of the Equation.
Ex :- Product of First & last term = 2
Product of Splitted term = 2 × 1 = 2.