Find Zero of the Polynomial
x²−8x+15=0
Answers
Answered by
2
x²-8x+15
x²-3x-5x+15
x(x-3)-5(x-3)
(x-3)(x-5)
x=3,5
Answered by
2
Answer:
5 and 3
Step-by-step explanation:
we have,
x²-8x+15 = 0
x²-5x-3x+15 = 0
x(x-5)-3(x-5) = 0
(x-5)(x-3) = 0
so, now
x-5 = 0 and x-3 = 0
x = 5 and x = 3
so zeros of this polynomial are,,
5 and 3
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