Find zero of the polynomial y^2-1/2y+1/16
Answers
Answered by
4
Answer:
y² - y/2 + 1/16 = 0
=> y² - y/4 - y/4 + 1/16 = 0
=> y(y-1/4) - 1/4(y-1/4) = 0
=>(y-1/4)² = 0
y = 1/4 , 1/4
Similar questions