Question

find zero of x2-5x and verify the coefficients​

Answer 1

Step-by-step explanation:

x²-5x=0

=> x(x-5) =0

=> x=0

x-5=0

=> x=0

x=5

VERIFICATION

1) 0²-5*X=0

0-0=0

0=0

2) 5²-5*5=0

25-25=0

0=0

hence proved

LHS=RHS