Question

find zero of x²+99x+127​

Answer 1

Answer:

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Step-by-step explanation:

here a=>1;b=>99;c=>127

By applying this$\frac{-b+ or - \sqrt{b^{2} -4ac} }{2a}$

we get, x=$\frac{-99+\sqrt{9293} }{2} and \frac{-99-\sqrt{9293} }{2}$

On solving we get x=1.2999 or -97.7001

I hope this helps you:)