Question

find zero's of 4x squre-7

Answer 1

Zeros for
$4 {x}^{2} - 7 \\ 4 {x}^{2} = 7 \\ {x}^{2} = \frac{7}{4} \\ x = \sqrt{ \frac{7}{4} }$

Answer 2

☀️Hey here is you answer☀️

4x^2 - 7 = 0

(2x)^2 - (√7) = 0

(2x - √7)(2x + √7) = 0

Either,

2x - √7 = 0. or 2x + √7 = 0

2x = √7 or 2x = - √7

x = √7/2. or . x = - √7/2

I HOPE IT WILL HELP YOU ☺️☺️