Find zeroee of quadratic polynomial f(x) =6x²-3 and verify the relationship between zeroes and its coffiecient
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f(x) = 6 x^2 - 3
= 3(2 x^2 - 1)
suppose f(x) = 0
then 2 x^2 - 1 = 0
2 x^2 = 1
x^2 = 1 / 2
x = + 1 / √2
the zeros of f(x) = +1/√2 , -1/√ 2
sum of the root = -b/a = -0/6 = 0
product of the roots = c / a = - 3 / 6 = -1 / 2
= 3(2 x^2 - 1)
suppose f(x) = 0
then 2 x^2 - 1 = 0
2 x^2 = 1
x^2 = 1 / 2
x = + 1 / √2
the zeros of f(x) = +1/√2 , -1/√ 2
sum of the root = -b/a = -0/6 = 0
product of the roots = c / a = - 3 / 6 = -1 / 2
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