Question

find zeroes
3х2+8x+5
​

Answer 1

Answer:

3x²+8x+5

3x²+5x+3x+5

x(3x+5) +1(3x+5)

(x+1) (3x+5)

x=-1, x=-5/3.

Answer 2

Question :

Find zeroes

${3x}^{2} + 8x + 5$

Answer :

$p_{(x)} = 0$

${3x}^{2} + 3x + 5x + 5 = 0$

$3x(x + 1) + 5(x + 1) = 0$

$(3x + 5)(x + 1) = 0$

$= \frac{ - 5}{3} \: or - 1$

Therefore, zeroes = -5/3, -1

Have a nice day!