Question

Find zeroes and also vefify
4u^2 + 8u

​

Answer 1

Answer:

zeroes will be... u=0 or -2

Step-by-step explanation:

4u^2+8u = 4u(u+2)

so, either u= 0/4=0 or u+2=0 =>u= (-2)

Answer 2

Let f(u)=4u2+8u

To calculate the zeros of the given equation, put f(u)=0.

4u2+8u=0

4u(u+2)=0

u=0,u=−2

The zeros of the given equation is 0 and −2.

Sum of the zeros is 0+(−2)=−2.

Product of the zeros is 0×−2=0.

According to the given equation,

The sum of the zeros is,

a−b=4−(8)=−2

The product of the zeros is,ac=40=0

Hence, it is verified

______________________

Thank you so much for your thanks