Math, asked by Varun2474, 3 months ago

Find Zeroes for x^3+x^2-5*x+3

Answers

Answered by itsnasreensahaikh

Step-by-step explanation:

x^3+x^2-5*x+3x^3+x^2-5*x+3x^3+x^2-5*x+3

x^3+x^2-5*x+3x^3+x^2-5*x+3x^3+x^2-5*x+3x^3+x^2-5*x+3x^3+x^2-5*x+3x^3+x^2-5*x+3x^3+x^2-5*x+3x^3+x^2-5*x+3x^3+x^2-5*x+3x^3+x^2-5*x+3x^3+x^2-5*x+3x^3+x^2-5*x+3x^3+x^2-5*x+3x^3+x^2-5*x+3x^3+x^2-5*x+3

3x^3+x^2-5*x+3x^3+x^2-5*x+3x^3+x^2-5*x+3x^3+x^2-5*x+3x^3+x^2-5*x+3x^3+x^2-5*x+3x^3+x^2-5*x+3x^3+x^2-5*x+3x^3+x^2-5*x+3x^3+x^2-5*x+3x^3+x^2-5*x+3

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