Math, asked by sima778812, 3 months ago

In right triangled ABC right angled at B ,a line DE is drawn through the mid

point D of AB and parallel to BC.If AB=9 cm, BC=12 cm. AE=?

13 cm

10 cm

8.5 cm

7.5 cm​

Answers

Answered by munnikumunniku3576
1

Answer:

answer is 7.5 cm

In right triangled ABC right angled at B ,a line DE is drawn through the mid point D of AB and parallel to BC.If AB=9 cm, BC=12 cm. AE=?

a)13 cm

b)10 cm

c)8.5 cm

d)7.5 cm

Correct answer is option 'D'. Can you explain this answer?

Related Test: Test: Pythagoras Theorem

Class 10 Question

Genius Unidentified

May 14, 2019

Upvote | 15

Drishti Kumari

Apr 16, 2020

In a triangle ABC in which angle B = 90 degree So, AB is height of the given triangle = 9 cm Base of triangle i.e, BC = 12 cm DE is || to BC D is the mid point of side AB and E is the mid point of side AC By applying pythagoras AC^2 = AB^2 + BC^2 AC^2 = 9^2 + 12^2 AC^2 = 81 + 144 AC^2 = 225 AC = root under 225 AC = 15 cm E is the mid point of AC Therefore AE = AC / 2 AE = 15 / 2 AE = 7.5 cm That's why D is the correct option .

Upvote | 8

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