Question

Find zeroes of 9x²+4​

Answer 1

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$\huge\boxed{ANSWER}$

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The following quadratic doesn't have any real root.

As D is -ve here.

D = b² - 4ac

D = 0² - 4×9×4

D = -144

Since D is negative, The eqn doesn't have any real root.

Answer 2

Answer:+2/3or-2/3

Step-by-step explanation:a=9 b=0c=4

-b+_√b^2-4ac/2a

By substituting we get

+_12/18 i.e.+_2/3