Question

find zeroes of a) 3-4x b) (x+1)(x+3)​

Answer 1

Answer:

heya mate there's your answer

1) 3-4x=0

4x=3

x=3/4 is the required root of 3-4x

2)(x+1)(x+3)=0

x+1=0 and (x+3)=0

x=-1 x=-3

-1 and -3 are the required roots

hope it helps you

Thank you

Answer 2

To find zeroes of the equation put equation equals to zero...

⚛️ SOLUTIONS__

(a) 3 - 4x = 0

=> 3 = 4x

=> x = 3/4

(b) (x + 1)(x + 3) = 0

Then, => x + 1 = 0 => x = -1

and, => x + 3 = 0 => x = -3

x = -1 and -3

HOPE_IT_HELPS_✌✌✌