Question

find zeroes of given quadratic polynomial 2x^2-5x+7.

give step by step solution

Answer 1

solution: 2x^2-5x+7=0
(solving the quadratic equation)
we get the values of x in terms of iota(i)
i.e a complex root of the quadratic equation.
so, for x= 5+5.56i/4 and x= 5-5.56i/4
the value of the quadratic equation is 0
Thus these two numbers are the zeroes of the given quadratic equation.

Hope u got it :)