Question

if one root of quadratic eqn x^2-8x+k is 4+√3...find k
$x^{2} - 8x + k = 0$

Answer 1

here is the answer......

Answer 2

${x}^{2} - 8x + k = 0 \\ sum \: of \: roots \: = 8 \\ 4 + \sqrt{3} + \alpha = 8 \\ \alpha = 4 - \sqrt{3} \\ product = k \\ (4 + \sqrt{3} )(4 - \sqrt{3} ) = k \\ 16 -3 = k \\ k = 13$
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