find zeroes of p(x)=2x^2-3+5x and find relationship between zeroes
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first arrange it in2x^2+5x-3 then split the middle term
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2x^2+5x-3
2x^2-x+6x-3
2x(x-1) +3(x-1)
(2x+3) (x-1)
alpha=-3/2. beta =1
2x^2-x+6x-3
2x(x-1) +3(x-1)
(2x+3) (x-1)
alpha=-3/2. beta =1
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