find zeroes of p(x)=2x^2-8x+6 an relationship between zeroes
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hii...
let alpha and beta be the zeroes i.e. value of x
hope this helps !
let alpha and beta be the zeroes i.e. value of x
hope this helps !
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Anonymous:
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Answered by
1
answer is 8
x=0 put 0 in x
2(0)^2-8(0)+6
0^2-0+6
6+2=8
x=0 put 0 in x
2(0)^2-8(0)+6
0^2-0+6
6+2=8
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