Math, asked by 8076095263, 1 year ago

Find zeroes of polynomial F(x) =(underroot) 3x(to the power) 2+10x+7(underroot)3. class-x

Answers

Answered by AyushPeshane
2
f(x)=√3x^2+10x+7√3
=√3x^2+7x+3x+7√3
=x(√3x+7)+√3(√3x+7)
=(x+√3) (√3x+7)

x=-√3. or. x=-7/√3
Answered by mysticd
2
Hi ,

f(x) = √3x² +10x +7√3

let f(x)=0

√3x² +10x+7√3=0

√3x² +3x +7x +7√3=0

√3x²+√3×√3x +7x+7√3=0

√3x(x+√3)+7(x+√3)=0

(x+√3)(√3x+7)=0

Therefore,

x+√3=0 or √3x+7=0

x= -√3 or x = -7/√3

zeroes of the polynomial f(x ) are -√3 or

(-7/√3)

I hope this helps you.

:)
Similar questions