Find zeroes of polynomial F(x) =(underroot) 3x(to the power) 2+10x+7(underroot)3. class-x
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f(x)=√3x^2+10x+7√3
=√3x^2+7x+3x+7√3
=x(√3x+7)+√3(√3x+7)
=(x+√3) (√3x+7)
x=-√3. or. x=-7/√3
=√3x^2+7x+3x+7√3
=x(√3x+7)+√3(√3x+7)
=(x+√3) (√3x+7)
x=-√3. or. x=-7/√3
Answered by
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Hi ,
f(x) = √3x² +10x +7√3
let f(x)=0
√3x² +10x+7√3=0
√3x² +3x +7x +7√3=0
√3x²+√3×√3x +7x+7√3=0
√3x(x+√3)+7(x+√3)=0
(x+√3)(√3x+7)=0
Therefore,
x+√3=0 or √3x+7=0
x= -√3 or x = -7/√3
zeroes of the polynomial f(x ) are -√3 or
(-7/√3)
I hope this helps you.
:)
f(x) = √3x² +10x +7√3
let f(x)=0
√3x² +10x+7√3=0
√3x² +3x +7x +7√3=0
√3x²+√3×√3x +7x+7√3=0
√3x(x+√3)+7(x+√3)=0
(x+√3)(√3x+7)=0
Therefore,
x+√3=0 or √3x+7=0
x= -√3 or x = -7/√3
zeroes of the polynomial f(x ) are -√3 or
(-7/√3)
I hope this helps you.
:)
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