Question

Find zeroes of the polynomial mx2 + (m+n)x + n.

Pls answer as soon as possible.

Answer 1

Answer to your question:

Given,

The polynomial,

mx²+(m+n)x+n

=mx²+(m+n)x+n

=mx²+mx+nx+n

=mx(x+1)+n(x+1)

=(x+1)(mx+n)

We get (x+1)=0, (mx+n)=0

So, according to the rule, the value of x will be the zeros of the polynomial.

Either, x+1=0 => x=-1 or mx+n=0 => mx=-n => x =-n/m

Hence, the zeros of the polynomial are -1,-n/m